Tuesday, July 28, 2009

Can someone double check my work?

First of all, I appologize for posting this a few times. But I think I have finally gotten it!





An airplane cruises at 120 km/h in still air. one day, when the wind was blowing steady from the west, the airplane travelled west (flying into the wind) and landed at its destination after 1.5 g. The airplanes return trip (flying with the wind) was only 1.0h long. On both legs, the airplane travelled at its cruising speed (measured with respect to the air surrounding the airplane)





a)Write a system of equations that would allow you to determine the speed of the wind blowing that day and the distance travelled each way.





b) When solving the system of equations graphically, what equations would you enter into the equation editor? Fill in the blank calculator display.





c) Indicate what the variable X and Y represent.

Can someone double check my work?
Hi,





Let y = distance traveled one way.


Let x = speed of the wind





y = 1.5(120 - x) flying into the wind


y = 1(120 + x) flying with the wind





These equations simplify to:


y = 180 - 1.5x


y = 120 + x





Since they both equal y, set the 2 expressions equal to each other and solve for x.





180 - 1.5x = 120 + x


60 = 2.5x


24 = x. so the speed of the wind is 24 miles per hour.





If x = 24 and y = 120 + x, then y = 120 + 24, so y = 144.


The distance flown each way is 144 miles.





Wind speed = 24 mph %26lt;== ANSWER


Distance = 144 miles %26lt;== ANSWER





I hope that helps!! :-)


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